2x^2=-28x-80

Solution for 2x^2=-28x-80 equation:

2x^2=-28x-80

We move all terms to the left:

2x^2-(-28x-80)=0

We get rid of parentheses

2x^2+28x+80=0

a = 2; b = 28; c = +80;
Δ = b2-4ac
Δ = 282-4·2·80
Δ = 144
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{144}=12$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(28)-12}{2*2}=\frac{-40}{4}
=-10
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(28)+12}{2*2}=\frac{-16}{4}
=-4
$